derive third equation of motion

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derive third equation of motion

derive third equation of motion

Q1- Establish the relation v2 – u2 = 2as, where ‘u’ is the initial velocity, ‘v’ the final velocity, ‘a’ the uniform acceleration and ‘s’ is the distance covered by the body.

Third equation of motion – Let a body start with initial velocity u and after covering distance s under uniform acceleration a, its velocity becomes u in t seconds. Then
Average velocity =(u+v)/2
So the distance covered in time t is given by
s = Average velocity x Time =[u +vxt]/2
v+u =2s/t …….(i)
Using the first equation of motion : v = u + at
or v-u=at …….(ii)
Multiplying equations (i) and (ii), we get
(v + u) (v – u)= (2s x at)/t
or
v2 – u2 = 2as

derive third equation of motion,derive third equation of motion

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